For a sleeper density of (n+5), the number of sleepers required for constructing a broad gauge railway track of length 650 m is
A. 975
B. 918
C. 900
D. 880
Answer: Option C
This Question Belongs to Civil Engineering >> Railway Engineering
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The standard length of rail for Broad Gauge and Meter Gauge are respectively
A. 12 m and 12 m
B. 12 m and 13 m
C. 13 m and 12 m
D. 13 m and 13 m
Sleeper density = (n+5).
Length of one rail for broad gauge track 12.8 say 13(I,e n),
Sleeper density=13+5=18,
The Number of sleepers required for 650m lenth=(18/13)* 650.
=899.999 say 900.
write answer
for broad guage
length 13m
so 650/13=50
means 18 sleepers of 1 rail length .
so for 18= 18*50=900
Wrong answer correct answer is 918 check ies master for that